So, I have an e-sky 11.1V 1800mAh 20C Li-Po, but I haven't used it for about 4 years. I was quite sure I tried to discharge it to roughly around 50%, but probably discharged it a little further. Today I decided to check the voltage across the three cells.
The charge connector has black, yellow, blue and red wires. The voltages are as follows:
black->yellow: 3.81
black->blue: 7.62
black->red: 11.43
I originally assumed that the charge connector would be connected to the cells in parallel such that black would be connected to the negative terminal of all three cells, yellow would be connected to the positive of cell 1, blue to the positive of cell 2, and red to the positive of cell 3; however the results clearly show that I was wrong.
Based on the above readings it is clear that black is connected to the negative of cell 1, yellow is connected to the positive of cell 1 and the negative of cell 2, blue is connected to the positive of cell 2 and the negative of cell 3 and red is connected to the positive of cell 3. Thus, the above results show the all three cells have a voltage of 3.81:
cell 1 voltage = black->yellow = 3.81
cell 2 voltage = black->blue - black->yellow = 3.81
cell 3 voltage = black->red - black->blue = 3.81
My conclusion is that a voltage of 3.81 volts per cell is OK, and therefore I can recharge the battery and use it.
Anyway, I just wanted to check. Comments welcome. :-)
The charge connector has black, yellow, blue and red wires. The voltages are as follows:
black->yellow: 3.81
black->blue: 7.62
black->red: 11.43
I originally assumed that the charge connector would be connected to the cells in parallel such that black would be connected to the negative terminal of all three cells, yellow would be connected to the positive of cell 1, blue to the positive of cell 2, and red to the positive of cell 3; however the results clearly show that I was wrong.
Based on the above readings it is clear that black is connected to the negative of cell 1, yellow is connected to the positive of cell 1 and the negative of cell 2, blue is connected to the positive of cell 2 and the negative of cell 3 and red is connected to the positive of cell 3. Thus, the above results show the all three cells have a voltage of 3.81:
cell 1 voltage = black->yellow = 3.81
cell 2 voltage = black->blue - black->yellow = 3.81
cell 3 voltage = black->red - black->blue = 3.81
My conclusion is that a voltage of 3.81 volts per cell is OK, and therefore I can recharge the battery and use it.
Anyway, I just wanted to check. Comments welcome. :-)

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